3[2n-4(n+1)]=6n-12

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Solution for 3[2n-4(n+1)]=6n-12 equation:


Simplifying
3[2n + -4(n + 1)] = 6n + -12

Reorder the terms:
3[2n + -4(1 + n)] = 6n + -12
3[2n + (1 * -4 + n * -4)] = 6n + -12
3[2n + (-4 + -4n)] = 6n + -12

Reorder the terms:
3[-4 + 2n + -4n] = 6n + -12

Combine like terms: 2n + -4n = -2n
3[-4 + -2n] = 6n + -12
[-4 * 3 + -2n * 3] = 6n + -12
[-12 + -6n] = 6n + -12

Reorder the terms:
-12 + -6n = -12 + 6n

Add '12' to each side of the equation.
-12 + 12 + -6n = -12 + 12 + 6n

Combine like terms: -12 + 12 = 0
0 + -6n = -12 + 12 + 6n
-6n = -12 + 12 + 6n

Combine like terms: -12 + 12 = 0
-6n = 0 + 6n
-6n = 6n

Solving
-6n = 6n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6n' to each side of the equation.
-6n + -6n = 6n + -6n

Combine like terms: -6n + -6n = -12n
-12n = 6n + -6n

Combine like terms: 6n + -6n = 0
-12n = 0

Divide each side by '-12'.
n = 0

Simplifying
n = 0

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